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Research Papers

Adaptive Fuzzy Sliding Mode Control for MIMO Nonaffine Dutch-Roll System

[+] Author and Article Information
Yuhui Wang

Department of Automation Engineering,
Nanjing University of
Aeronautics and Astronautics,
No. 29, Jiangjun Road,
Nanjing 211106, Jiangsu, China
e-mail: wangyh@nuaa.edu.cn

Qingxian Wu

Professor
Department of Automation Engineering,
Nanjing University of
Aeronautics and Astronautics,
Nanjing 211106, Jiangsu, China
e-mail: wuqingxian@nuaa.edu.cn

Xinyan Liu

Department of Automation Engineering,
Nanjing University of
Aeronautics and Astronautics,
Nanjing 211106, Jiangsu, China
e-mail: Lexy_ac@nuaa.edu.cn

Contributed by the Dynamic Systems Division of ASME for publication in the JOURNAL OF DYNAMIC SYSTEMS, MEASUREMENT, AND CONTROL. Manuscript received May 4, 2016; final manuscript received March 16, 2017; published online June 28, 2017. Assoc. Editor: Yang Shi.

J. Dyn. Sys., Meas., Control 139(10), 101010 (Jun 28, 2017) (9 pages) Paper No: DS-16-1230; doi: 10.1115/1.4036551 History: Received May 04, 2016; Revised March 16, 2017

A robust fuzzy sliding mode controller is presented for a multiple-input–multiple-output (MIMO) Dutch-Roll system with nonaffine inputs and external disturbances. An integrating factor with a nonlinear saturation function is introduced to construct a nonlinear integral sliding mode (NISM) surface to provide better transient response than traditional sliding mode control. Fuzzy logic systems are employed to approximate the unknown nonaffine part of the system directly. Based on Lyapunov method, the tracking errors are guaranteed to be asymptotically stable with the additional adaptive compensation terms. To verify the feasibility and effectiveness of the proposed controller, the Dutch-Roll system is presented for simulation.

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Figures

Grahic Jump Location
Fig. 1

The graphs of the functions ξ

Grahic Jump Location
Fig. 2

The nonaffine control scheme for the Dutch-Roll system

Grahic Jump Location
Fig. 5

The dynamic responses of the aircraft at βd=0, ϕd=−0.1/(1+exp(t−5))+0.1/(1+exp(t−30)) with d1(x,t)=sin β cos t and d2(x,t)=cos ϕ sin t: (a) β, (b) ϕ, (c) ps, (d) rs, (e) δa, (f) δr, (g) s(t), and (h) ϑ̂

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